c# - Kendo DateTimePicker Culture Doesn't work Asp.net MVC -

i have kendo data picker display date, want have date information in french used efficient script in layout page bellow:

<script>         kendo.culture("fr-fr");     </script>     <script src="~/scripts/kendo/culture/kendo.fr-fr.js"></script>     <script src="~/scripts/kendo/kendo.tooltip.min.js"></script> </script> 

i add globalize script culture doesn’t change:

![<script type="text/javascript" src="~/scripts/globalize/globalize.js"></script>     <script type="text/javascript" src="~/scripts/globalize/cultures/globalize.culture.fr-fr.js"></script>][1] 

kendo datapicker image:

@chxzy here kendo datapicker

 @(html.kendo().datepickerfor(m => m./****).events(e => e.open("onopen")).footer("today - #=kendo.tostring(data, 'd') #").monthtemplate("# if ($.inarray(+data.date, birthdays) != -1) { #" +                                      "<div class=\"birthday\"></div>" +                                  "# } #" +                                  "#= data.value #")                    .htmlattributes(new { @class = "form-control" })                            .culture("fr-fr")     ) 

and here script code:

var today = new date(),     birthdays = [         +new date(today.getfullyear(), today.getmonth(), 11),         +new date(today.getfullyear(), today.getmonth() + 1, 6),         +new date(today.getfullyear(), today.getmonth() + 1, 27),         +new date(today.getfullyear(), today.getmonth() - 1, 3),         +new date(today.getfullyear(), today.getmonth() - 2, 22)     ];  function onopen() {     var dateviewcalendar = this.dateview.calendar;     if (dateviewcalendar) {         dateviewcalendar.element.width(340);     } }; 

can please try adding following datepicker js code.

$("#datepicker").kendodatepicker({   culture: "fr-fr",   //.... }) 

edit

after reviewing kendo mvc code, can try changing folowing think manually specifying format footer fix this.

this:

.footer("today - #=kendo.tostring(data, 'd') #") 

to this:

.footer("today - #=kendo.tostring(data, 'dd/mm/yyyy') #")