i created member function returning reference object.
i can like:
class foo { foo &ref(){ return *this; } } ref returning object this pointer.
is there way else return object without using this?
explain reason:
the reason don't want use this is: pointer occupy 4b in stack whereas reference share same memory
it sounds don't this and don't want dereference pointers. how about:
class foo { private: int dummy; public: foo& ref() { return reinterpret_cast<foo&>(dummy); } }; static_assert(std::is_standard_layout<foo>::value, "foo must standard-layout!"); because foo standard-layout class , dummy first non-static data member , there no base classes, address of dummy same of containing foo.
needless say, silly way return reference object , can't see possible justification doing way. not wanting write return *this; wanting add 2 integers without using +. makes no sense @ all.
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