unix - Replace a string in shell script using a variable -

i using below code replacing string inside shell script.

echo $line | sed -e 's/12345678/"$replace"/g' 

but it's getting replaced $replace instead of value of variable.

could tell went wrong?

if want interpret $replace, should not use single quotes since prevent variable substitution.

try:

echo $line | sed -e "s/12345678/\"${replace}\"/g" 

assuming want quotes put in. if don't want quotes, use:

echo $line | sed -e "s/12345678/${replace}/g" 

transcript:

pax> export replace=987654321 pax> echo x123456789x | sed "s/123456789/${replace}/" x987654321x pax> _ 

just careful ensure ${replace} doesn't have characters of significance sed (like / instance) since cause confusion unless escaped. if, say, you're replacing 1 number another, shouldn't problem.