scala - Why does `Array(0,1,2) == Array(0,1,2)` not return the expected result? -

as far understand, scala's == defines natural equality of 2 objects.

i expected array(0,1,2) == array(0,1,2) compares natural equality. example, checks if elements of array return true when compared corresponding elements of other array.

people told me scala's array java [] compares identity. wouldn't more meaningful override array'sequals method compare natural equality instead?

scala 2.7 tried add functionality java [] arrays, , ran corner cases problematic. scala 2.8 has declared array[t] t[], provides wrappers , equivalents.

try following in 2.8 (edit/note: of rc3, genericarray arrayseq--thanks retronym pointing out):

import scala.collection.mutable.{genericarray=>garray, wrappedarray=>warray} scala> garray(0,1,2) == garray(0,1,2) res0: boolean = true  scala> (array(0,1,2):warray[int]) == (array(0,1,2):warray[int]) res1: boolean = true 

genericarray acts array, except scala collections goodies added in. wrappedarray wraps java [] array; above, i've cast plain array (easier calling implicit conversion function) , compared wrapped arrays. these wrappers, though backed [] array, give collection goodies.