codeigniter - Displaying the data dynamically using Ajax -

in code, after clicking button, data added in database already. wanted after adding data, query total of chosen item , display without loading page.

this code now:

my view:

<p id='state'><i class='fa fa-thumbs-up'></i><span id="likethis"><?php echo $countlike;?></span> likes &bull; <i class='fa fa-thumbs-down'></i><?php echo $countdislike;?> dislikes &bull;<i class='fa fa-thumbs-down'></i><a href='<?php echo base_url();?>index.php/photocheese/deleteuploadpic/<?php echo $row['uploadid'];?>'>delete picture</a></p>  <input type="button" onclick="getval(this.value)" class='detailbutton1' name='like_name' id='like_id' value='<?php echo $link;?>' title='like post'><i class='fa fa-thumbs-up'></i> like</input> 

javascript:

function getval(value) { jquery.ajax({ type:"get", url: "<?php echo base_url();?>index.php/photocheese/like_total/", datatype:'json', data: {like_id : value}, success: function(res){ alert(res.no_likes); if(res){ jquery("#likethis").html(res.no_likes); }
} });

controller:

public function like_total(){         $id = $this->session->userdata('userid');         $upload = $this->input->get('like_id');         $data = array('like' => 1,                         'userid'=>$id,                         'uploadid'=>$_get['like_id']);          $result = $this->photocheese_model->get_like_total($data,$upload);           return json_encode($result);     } 

model:

public function get_like_total($data,$uplaod){         $success = $this->db->insert('tbl_like',$data);          if($success){             $this->db->select('uploadid,sum(`like`) no_likes',false);             $this->db->where('uploadid',$upload);             $this->db->where('like !=',2);              $query = $this->db->get();           }         return $query->result_array();     } 

this code not display total_likes. what's wrong one?

this looks decent code me

public function like_total(){     $id = $this->session->userdata('userid');     $upload = $this->input->get('like_id');     $data = array('like' => 1,                     'userid'=>$id,                     'uploadid'=>$_get['like_id']);      $result = $this->photocheese_model->get_like_total($data,$upload);       return json_encode($result); } 

just 1 try.. change

return json_encode($result)

to

echo json_encode($result)

this example may in future jquery ajax php example