python - My program is working, but I don't want overlapping of adjacent pairs. For e.g; if i have 'aaa', the number of pairs should be only 1, not 2 -

def pairs(message, num_pair, i):   if == len(message) - 1:     return("number of pairs:", num_pair)    else:     if message[i]==message[i+1]:       return pairs(message, num_pair+1, i+1)     else:       return pairs(message, num_pair, i+1)   def main():   message = input("enter message: \n")   num_pair = 0   = 0   message, p = pairs(message, num_pair, i)   print (message, p)  main() 

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enter message:  aaaa number of pairs: 3 

however, output should 2, when finish comparing 2 characters , find same, should move other character second one.

after detecting pair skip completely. means instead of advancing 1 char advance index 2.