python - Regex to segregate list of strings and regexs -

i have python input list containing both strings , regexs.

str_regex = ['normal_string_1', ''^(?![_\-])[a-za-z0-9\-_]+$', 'normal_string_2']  

i need segregate list list of strings , list of regexs. in summary below input , required output.

input :

['normal_string_1', ''^(?![_\-])[a-za-z0-9\-_]+$', 'normal_string_2'] 

output :

['normal_string_1', 'normal_string_2'], ['^(?![_\-])[a-za-z0-9\-_]+$'] 

i planning form regex this. "should contains [a-z] , [a-z]". best way it?

if understand problem correctly, want pass string function along list of different regexes, returning regex matches. should trick:

import re def contains(string, regexes):   lst = []   regex in regexes:     match = re.findall(regex, string)     if len(match) > 0 , len(match[0]) == len(string):       return string + " contains \"" + regex + "\""   return "no matching regex found"  if __name__ == "__main__":   regexes = [     "[a-z]+",     # lower case     "[a-z]+",     # upper case     "[a-za-z]+",  # mixed case     "\d+",        # digits     "[a-z\d]+",   # digits , lower case     "[a-z\d]+",   # digits , upper case     "[a-za-z\d]+" # digits , mixed case   ]   print contains("should" , regexes)   print contains("should" , regexes)   print contains("should" , regexes)   print contains("123"    , regexes)   print contains("123as"  , regexes)   print contains("123as"  , regexes)   print contains("123as"  , regexes) 

the above prints

should contains "[a-z]+" should contains "[a-z]+" should contains "[a-za-z]+" 123 contains "\d+" 123as contains "[a-z\d]+" 123as contains "[a-z\d]+" 123as contains "[a-za-z\d]+"